(3x-8)=11+(x+11)

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Solution for (3x-8)=11+(x+11) equation: 



(3x-8)=11+(x+11)

We move all terms to the left:

(3x-8)-(11+(x+11))=0

We get rid of parentheses

3x-(11+(x+11))-8=0



We calculate terms in parentheses: -(11+(x+11)), so:

11+(x+11)

determiningTheFunctionDomain
(x+11)+11

We get rid of parentheses

x+11+11

We add all the numbers together, and all the variables

x+22

Back to the equation:

-(x+22)



We get rid of parentheses

3x-x-22-8=0

We add all the numbers together, and all the variables

2x-30=0

We move all terms containing x to the left, all other terms to the right

2x=30

x=30/2

x=15

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