(3x-7)/9+x=(3x+7)/3+2

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Solution for (3x-7)/9+x=(3x+7)/3+2 equation: 



(3x-7)/9+x=(3x+7)/3+2

We move all terms to the left:

(3x-7)/9+x-((3x+7)/3+2)=0

We add all the numbers together, and all the variables

x+(3x-7)/9-((3x+7)/3+2)=0

We calculate fractions


x+(9x-21)/()+(-((3x+7)*9)/()=0



We calculate terms in parentheses: +(-((3x+7)*9)/(), so:

-((3x+7)*9)/(

We multiply all the terms by the denominator


-((3x+7)*9)



We calculate terms in parentheses: -((3x+7)*9), so:

(3x+7)*9

We multiply parentheses

27x+63

Back to the equation:

-(27x+63)



We get rid of parentheses

-27x-63

Back to the equation:

+(-27x-63)



We get rid of parentheses

x+(9x-21)/()-27x-63=0

We multiply all the terms by the denominator


x*()+(9x-21)-27x*()-63*()=0

We add all the numbers together, and all the variables

x*()+(9x-21)-27x*()=0

We get rid of parentheses

x*()+9x-27x*()-21=0

We add all the numbers together, and all the variables

9x+x*()-27x*()-21=0

We move all terms containing x to the left, all other terms to the right

9x+x*()-27x*()=21

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