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2a+1/6a=-4
We move all terms to the left:
2a+1/6a-(-4)=0
Domain of the equation: 6a!=0We add all the numbers together, and all the variables
a!=0/6
a!=0
a∈R
2a+1/6a+4=0
We multiply all the terms by the denominator
2a*6a+4*6a+1=0
Wy multiply elements
12a^2+24a+1=0
a = 12; b = 24; c = +1;
Δ = b2-4ac
Δ = 242-4·12·1
Δ = 528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{528}=\sqrt{16*33}=\sqrt{16}*\sqrt{33}=4\sqrt{33}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{33}}{2*12}=\frac{-24-4\sqrt{33}}{24} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{33}}{2*12}=\frac{-24+4\sqrt{33}}{24} $
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