(3x-7)+(4x+19)=115

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Solution for (3x-7)+(4x+19)=115 equation: 



(3x-7)+(4x+19)=115

We move all terms to the left:

(3x-7)+(4x+19)-(115)=0

We get rid of parentheses

3x+4x-7+19-115=0

We add all the numbers together, and all the variables

7x-103=0

We move all terms containing x to the left, all other terms to the right

7x=103

x=103/7

x=14+5/7

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