(x-4)+(6x)=(8x-14)

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Solution for (x-4)+(6x)=(8x-14) equation: 



(x-4)+(6x)=(8x-14)

We move all terms to the left:

(x-4)+(6x)-((8x-14))=0

We add all the numbers together, and all the variables

6x+(x-4)-((8x-14))=0

We get rid of parentheses

6x+x-((8x-14))-4=0



We calculate terms in parentheses: -((8x-14)), so:

(8x-14)

We get rid of parentheses

8x-14

Back to the equation:

-(8x-14)



We add all the numbers together, and all the variables

7x-(8x-14)-4=0

We get rid of parentheses

7x-8x+14-4=0

We add all the numbers together, and all the variables

-1x+10=0

We move all terms containing x to the left, all other terms to the right

-x=-10

x=-10/-1

x=+10

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