(3x-6)/2=(3x+9)/7

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Solution for (3x-6)/2=(3x+9)/7 equation: 



(3x-6)/2=(3x+9)/7

We move all terms to the left:

(3x-6)/2-((3x+9)/7)=0

We calculate fractions


3x/()+(-((3x+9)*2)/()=0



We calculate terms in parentheses: +(-((3x+9)*2)/(), so:

-((3x+9)*2)/(

We multiply all the terms by the denominator


-((3x+9)*2)



We calculate terms in parentheses: -((3x+9)*2), so:

(3x+9)*2

We multiply parentheses

6x+18

Back to the equation:

-(6x+18)



We get rid of parentheses

-6x-18

Back to the equation:

+(-6x-18)



We get rid of parentheses

3x/()-6x-18=0

We multiply all the terms by the denominator


3x-6x*()-18*()=0

We add all the numbers together, and all the variables

3x-6x*()=0

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