(3x-6)(x+16)=0

Solution for (3x-6)(x+16)=0 equation:

(3x-6)(x+16)=0

We multiply parentheses ..

(+3x^2+48x-6x-96)=0

We get rid of parentheses

3x^2+48x-6x-96=0

We add all the numbers together, and all the variables

3x^2+42x-96=0

a = 3; b = 42; c = -96;
Δ = b2-4ac
Δ = 422-4·3·(-96)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-54}{2*3}=\frac{-96}{6}
=-16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+54}{2*3}=\frac{12}{6}
=2
$