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(2x-4)(5x+5)=0
We multiply parentheses ..
(+10x^2+10x-20x-20)=0
We get rid of parentheses
10x^2+10x-20x-20=0
We add all the numbers together, and all the variables
10x^2-10x-20=0
a = 10; b = -10; c = -20;
Δ = b2-4ac
Δ = -102-4·10·(-20)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-30}{2*10}=\frac{-20}{20} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+30}{2*10}=\frac{40}{20} =2 $
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