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(3x-6)(2x+46)=90
We move all terms to the left:
(3x-6)(2x+46)-(90)=0
We multiply parentheses ..
(+6x^2+138x-12x-276)-90=0
We get rid of parentheses
6x^2+138x-12x-276-90=0
We add all the numbers together, and all the variables
6x^2+126x-366=0
a = 6; b = 126; c = -366;
Δ = b2-4ac
Δ = 1262-4·6·(-366)
Δ = 24660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24660}=\sqrt{36*685}=\sqrt{36}*\sqrt{685}=6\sqrt{685}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-6\sqrt{685}}{2*6}=\frac{-126-6\sqrt{685}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+6\sqrt{685}}{2*6}=\frac{-126+6\sqrt{685}}{12} $
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