(3x-5)/(32)=(5x-5)/(56)

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Solution for (3x-5)/(32)=(5x-5)/(56) equation: 



(3x-5)/(32)=(5x-5)/(56)

We move all terms to the left:

(3x-5)/(32)-((5x-5)/(56))=0

We calculate fractions


3x/()+(-((5x-5)*32)/()=0



We calculate terms in parentheses: +(-((5x-5)*32)/(), so:

-((5x-5)*32)/(

We multiply all the terms by the denominator


-((5x-5)*32)



We calculate terms in parentheses: -((5x-5)*32), so:

(5x-5)*32

We multiply parentheses

160x-160

Back to the equation:

-(160x-160)



We get rid of parentheses

-160x+160

Back to the equation:

+(-160x+160)



We get rid of parentheses

3x/()-160x+160=0

We multiply all the terms by the denominator


3x-160x*()+160*()=0

We add all the numbers together, and all the variables

3x-160x*()=0

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