3x2-18x-88=0

Solution for 3x2-18x-88=0 equation:

3x^2-18x-88=0

a = 3; b = -18; c = -88;
Δ = b2-4ac
Δ = -182-4·3·(-88)
Δ = 1380
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1380}=\sqrt{4*345}=\sqrt{4}*\sqrt{345}=2\sqrt{345}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{345}}{2*3}=\frac{18-2\sqrt{345}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{345}}{2*3}=\frac{18+2\sqrt{345}}{6}
$