(3x-5)*(3x-5)=0

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Solution for (3x-5)*(3x-5)=0 equation: 



(3x-5)(3x-5)=0

We multiply parentheses ..

(+9x^2-15x-15x+25)=0

We get rid of parentheses

9x^2-15x-15x+25=0

We add all the numbers together, and all the variables

9x^2-30x+25=0

a = 9; b = -30; c = +25;
Δ = b2-4ac
Δ = -302-4·9·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{30}{18}=1+2/3$

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