8y-3(4-2y)=3(y+3)+1

Solution for 8y-3(4-2y)=3(y+3)+1 equation:

8y-3(4-2y)=3(y+3)+1

We move all terms to the left:

8y-3(4-2y)-(3(y+3)+1)=0

We add all the numbers together, and all the variables

8y-3(-2y+4)-(3(y+3)+1)=0

We multiply parentheses

8y+6y-(3(y+3)+1)-12=0


We calculate terms in parentheses: -(3(y+3)+1), so:

3(y+3)+1

We multiply parentheses

3y+9+1

We add all the numbers together, and all the variables

3y+10

Back to the equation:

-(3y+10)


We add all the numbers together, and all the variables

14y-(3y+10)-12=0

We get rid of parentheses

14y-3y-10-12=0

We add all the numbers together, and all the variables

11y-22=0

We move all terms containing y to the left, all other terms to the right

11y=22

y=22/11

y=2