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(3x-40)=(2x+20)
We move all terms to the left:
(3x-40)-((2x+20))=0
We get rid of parentheses
3x-((2x+20))-40=0
We calculate terms in parentheses: -((2x+20)), so:We get rid of parentheses
(2x+20)
We get rid of parentheses
2x+20
Back to the equation:
-(2x+20)
3x-2x-20-40=0
We add all the numbers together, and all the variables
x-60=0
We move all terms containing x to the left, all other terms to the right
x=60
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