(3x-4)/2=(2x+12)/5

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Solution for (3x-4)/2=(2x+12)/5 equation: 



(3x-4)/2=(2x+12)/5

We move all terms to the left:

(3x-4)/2-((2x+12)/5)=0

We calculate fractions


3x/()+(-((2x+12)*2)/()=0



We calculate terms in parentheses: +(-((2x+12)*2)/(), so:

-((2x+12)*2)/(

We multiply all the terms by the denominator


-((2x+12)*2)



We calculate terms in parentheses: -((2x+12)*2), so:

(2x+12)*2

We multiply parentheses

4x+24

Back to the equation:

-(4x+24)



We get rid of parentheses

-4x-24

Back to the equation:

+(-4x-24)



We get rid of parentheses

3x/()-4x-24=0

We multiply all the terms by the denominator


3x-4x*()-24*()=0

We add all the numbers together, and all the variables

3x-4x*()=0

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