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5x(2x+12)=125
We move all terms to the left:
5x(2x+12)-(125)=0
We multiply parentheses
10x^2+60x-125=0
a = 10; b = 60; c = -125;
Δ = b2-4ac
Δ = 602-4·10·(-125)
Δ = 8600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8600}=\sqrt{100*86}=\sqrt{100}*\sqrt{86}=10\sqrt{86}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-10\sqrt{86}}{2*10}=\frac{-60-10\sqrt{86}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+10\sqrt{86}}{2*10}=\frac{-60+10\sqrt{86}}{20} $
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