(3x-4)+(6x+2)=5x+22

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Solution for (3x-4)+(6x+2)=5x+22 equation: 



(3x-4)+(6x+2)=5x+22

We move all terms to the left:

(3x-4)+(6x+2)-(5x+22)=0

We get rid of parentheses

3x+6x-5x-4+2-22=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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