1=(n-4)/9

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Solution for 1=(n-4)/9 equation: 



1=(n-4)/9

We move all terms to the left:

1-((n-4)/9)=0

We multiply all the terms by the denominator


-((n-4)+1*9)=0



We calculate terms in parentheses: -((n-4)+1*9), so:

(n-4)+1*9

We add all the numbers together, and all the variables

(n-4)+9

We get rid of parentheses

n-4+9

We add all the numbers together, and all the variables

n+5

Back to the equation:

-(n+5)



We get rid of parentheses

-n-5=0

We add all the numbers together, and all the variables

-1n-5=0

We move all terms containing n to the left, all other terms to the right

-n=5

n=5/-1

n=-5

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