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(3x-39)(2x+14)=180
We move all terms to the left:
(3x-39)(2x+14)-(180)=0
We multiply parentheses ..
(+6x^2+42x-78x-546)-180=0
We get rid of parentheses
6x^2+42x-78x-546-180=0
We add all the numbers together, and all the variables
6x^2-36x-726=0
a = 6; b = -36; c = -726;
Δ = b2-4ac
Δ = -362-4·6·(-726)
Δ = 18720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18720}=\sqrt{144*130}=\sqrt{144}*\sqrt{130}=12\sqrt{130}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-12\sqrt{130}}{2*6}=\frac{36-12\sqrt{130}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+12\sqrt{130}}{2*6}=\frac{36+12\sqrt{130}}{12} $
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