(7-2x)1=(x-5)6

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Solution for (7-2x)1=(x-5)6 equation: 



(7-2x)1=(x-5)6

We move all terms to the left:

(7-2x)1-((x-5)6)=0

We add all the numbers together, and all the variables

(-2x+7)1-((x-5)6)=0



We calculate terms in parentheses: -((x-5)6), so:

(x-5)6

We multiply parentheses

6x-30

Back to the equation:

-(6x-30)



We get rid of parentheses

(-2x+7)1-6x+30=0

We add all the numbers together, and all the variables

-6x+(-2x+7)1+30=0

We move all terms containing x to the left, all other terms to the right

-6x+(-2x+7)1=-30

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