(3x-32)=2(x+8)

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Solution for (3x-32)=2(x+8) equation: 



(3x-32)=2(x+8)

We move all terms to the left:

(3x-32)-(2(x+8))=0

We get rid of parentheses

3x-(2(x+8))-32=0



We calculate terms in parentheses: -(2(x+8)), so:

2(x+8)

We multiply parentheses

2x+16

Back to the equation:

-(2x+16)



We get rid of parentheses

3x-2x-16-32=0

We add all the numbers together, and all the variables

x-48=0

We move all terms containing x to the left, all other terms to the right

x=48

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