(3x-32)=(2x+16)/2

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Solution for (3x-32)=(2x+16)/2 equation: 



(3x-32)=(2x+16)/2

We move all terms to the left:

(3x-32)-((2x+16)/2)=0

We get rid of parentheses

3x-((2x+16)/2)-32=0

We multiply all the terms by the denominator


3x*2)-((2x+16)-32*2)=0

We add all the numbers together, and all the variables

3x*2)-((2x+16)=0

Wy multiply elements

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$

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