(3x-3)+(x-3)=(2x-1)+(2x-1)+(2x)

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Solution for (3x-3)+(x-3)=(2x-1)+(2x-1)+(2x) equation: 



(3x-3)+(x-3)=(2x-1)+(2x-1)+(2x)

We move all terms to the left:

(3x-3)+(x-3)-((2x-1)+(2x-1)+(2x))=0

We get rid of parentheses

3x+x-((2x-1)+(2x-1)+2x)-3-3=0



We calculate terms in parentheses: -((2x-1)+(2x-1)+2x), so:

(2x-1)+(2x-1)+2x

We add all the numbers together, and all the variables

2x+(2x-1)+(2x-1)

We get rid of parentheses

2x+2x+2x-1-1

We add all the numbers together, and all the variables

6x-2

Back to the equation:

-(6x-2)



We add all the numbers together, and all the variables

4x-(6x-2)-6=0

We get rid of parentheses

4x-6x+2-6=0

We add all the numbers together, and all the variables

-2x-4=0

We move all terms containing x to the left, all other terms to the right

-2x=4

x=4/-2

x=-2

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