(2y-1)(7+y)=0

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Solution for (2y-1)(7+y)=0 equation:



(2y-1)(7+y)=0
We add all the numbers together, and all the variables
(2y-1)(y+7)=0
We multiply parentheses ..
(+2y^2+14y-1y-7)=0
We get rid of parentheses
2y^2+14y-1y-7=0
We add all the numbers together, and all the variables
2y^2+13y-7=0
a = 2; b = 13; c = -7;
Δ = b2-4ac
Δ = 132-4·2·(-7)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-15}{2*2}=\frac{-28}{4} =-7 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+15}{2*2}=\frac{2}{4} =1/2 $

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