(3x-2=2x+30)

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Solution for (3x-2=2x+30) equation: 



(3x-2=2x+30)

We move all terms to the left:

(3x-2-(2x+30))=0



We calculate terms in parentheses: +(3x-2-(2x+30)), so:

3x-2-(2x+30)

determiningTheFunctionDomain
3x-(2x+30)-2

We get rid of parentheses

3x-2x-30-2

We add all the numbers together, and all the variables

x-32

Back to the equation:

+(x-32)



We get rid of parentheses

x-32=0

We move all terms containing x to the left, all other terms to the right

x=32

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