2(40-5x)=10x+5(1-x)

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Solution for 2(40-5x)=10x+5(1-x) equation: 



2(40-5x)=10x+5(1-x)

We move all terms to the left:

2(40-5x)-(10x+5(1-x))=0

We add all the numbers together, and all the variables

2(-5x+40)-(10x+5(-1x+1))=0

We multiply parentheses

-10x-(10x+5(-1x+1))+80=0



We calculate terms in parentheses: -(10x+5(-1x+1)), so:

10x+5(-1x+1)

We multiply parentheses

10x-5x+5

We add all the numbers together, and all the variables

5x+5

Back to the equation:

-(5x+5)



We get rid of parentheses

-10x-5x-5+80=0

We add all the numbers together, and all the variables

-15x+75=0

We move all terms containing x to the left, all other terms to the right

-15x=-75

x=-75/-15

x=+5

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