(3x-29)=(2x+20)

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Solution for (3x-29)=(2x+20) equation: 



(3x-29)=(2x+20)

We move all terms to the left:

(3x-29)-((2x+20))=0

We get rid of parentheses

3x-((2x+20))-29=0



We calculate terms in parentheses: -((2x+20)), so:

(2x+20)

We get rid of parentheses

2x+20

Back to the equation:

-(2x+20)



We get rid of parentheses

3x-2x-20-29=0

We add all the numbers together, and all the variables

x-49=0

We move all terms containing x to the left, all other terms to the right

x=49

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