3/4(6x+1)-3x=1/4(2x+4)

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Solution for 3/4(6x+1)-3x=1/4(2x+4) equation:



3/4(6x+1)-3x=1/4(2x+4)
We move all terms to the left:
3/4(6x+1)-3x-(1/4(2x+4))=0
Domain of the equation: 4(6x+1)!=0
x∈R
Domain of the equation: 4(2x+4))!=0
x∈R
We add all the numbers together, and all the variables
-3x+3/4(6x+1)-(1/4(2x+4))=0
We calculate fractions
-3x+(12x2/(4(6x+1)*4(2x+4)))+(-4x6/(4(6x+1)*4(2x+4)))=0
We calculate terms in parentheses: +(12x2/(4(6x+1)*4(2x+4))), so:
12x2/(4(6x+1)*4(2x+4))
We multiply all the terms by the denominator
12x2
We add all the numbers together, and all the variables
12x^2
Back to the equation:
+(12x^2)
We calculate terms in parentheses: +(-4x6/(4(6x+1)*4(2x+4))), so:
-4x6/(4(6x+1)*4(2x+4))
We multiply all the terms by the denominator
-4x6
We add all the numbers together, and all the variables
-4x^6
We do not support expression: x^6

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