(3x-20)=(x+18)

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Solution for (3x-20)=(x+18) equation: 



(3x-20)=(x+18)

We move all terms to the left:

(3x-20)-((x+18))=0

We get rid of parentheses

3x-((x+18))-20=0



We calculate terms in parentheses: -((x+18)), so:

(x+18)

We get rid of parentheses

x+18

Back to the equation:

-(x+18)



We get rid of parentheses

3x-x-18-20=0

We add all the numbers together, and all the variables

2x-38=0

We move all terms containing x to the left, all other terms to the right

2x=38

x=38/2

x=19

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