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1/2x+3/3x=5/6
We move all terms to the left:
1/2x+3/3x-(5/6)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/2x+3/3x-(+5/6)=0
We get rid of parentheses
1/2x+3/3x-5/6=0
We calculate fractions
(-90x^2)/216x^2+108x/216x^2+216x/216x^2=0
We multiply all the terms by the denominator
(-90x^2)+108x+216x=0
We add all the numbers together, and all the variables
(-90x^2)+324x=0
We get rid of parentheses
-90x^2+324x=0
a = -90; b = 324; c = 0;
Δ = b2-4ac
Δ = 3242-4·(-90)·0
Δ = 104976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{104976}=324$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(324)-324}{2*-90}=\frac{-648}{-180} =3+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(324)+324}{2*-90}=\frac{0}{-180} =0 $
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