(3x-20)=(7x+30)=(2x+50)

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Solution for (3x-20)=(7x+30)=(2x+50) equation: 



(3x-20)=(7x+30)=(2x+50)

We move all terms to the left:

(3x-20)-((7x+30))=0

We get rid of parentheses

3x-((7x+30))-20=0



We calculate terms in parentheses: -((7x+30)), so:

(7x+30)

We get rid of parentheses

7x+30

Back to the equation:

-(7x+30)



We get rid of parentheses

3x-7x-30-20=0

We add all the numbers together, and all the variables

-4x-50=0

We move all terms containing x to the left, all other terms to the right

-4x=50

x=50/-4

x=-12+1/2

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