(3x-2)/18+x=(3x+2)/3+1

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Solution for (3x-2)/18+x=(3x+2)/3+1 equation: 



(3x-2)/18+x=(3x+2)/3+1

We move all terms to the left:

(3x-2)/18+x-((3x+2)/3+1)=0

We add all the numbers together, and all the variables

x+(3x-2)/18-((3x+2)/3+1)=0

We calculate fractions


x+(9x-6)/()+(-((3x+2)*18)/()=0



We calculate terms in parentheses: +(-((3x+2)*18)/(), so:

-((3x+2)*18)/(

We multiply all the terms by the denominator


-((3x+2)*18)



We calculate terms in parentheses: -((3x+2)*18), so:

(3x+2)*18

We multiply parentheses

54x+36

Back to the equation:

-(54x+36)



We get rid of parentheses

-54x-36

Back to the equation:

+(-54x-36)



We get rid of parentheses

x+(9x-6)/()-54x-36=0

We multiply all the terms by the denominator


x*()+(9x-6)-54x*()-36*()=0

We add all the numbers together, and all the variables

x*()+(9x-6)-54x*()=0

We get rid of parentheses

x*()+9x-54x*()-6=0

We add all the numbers together, and all the variables

9x+x*()-54x*()-6=0

We move all terms containing x to the left, all other terms to the right

9x+x*()-54x*()=6

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