6x(3+3x)+39=9x(11+2x)-3x

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Solution for 6x(3+3x)+39=9x(11+2x)-3x equation: 



6x(3+3x)+39=9x(11+2x)-3x

We move all terms to the left:

6x(3+3x)+39-(9x(11+2x)-3x)=0

We add all the numbers together, and all the variables

6x(3x+3)-(9x(2x+11)-3x)+39=0

We multiply parentheses

18x^2+18x-(9x(2x+11)-3x)+39=0



We calculate terms in parentheses: -(9x(2x+11)-3x), so:

9x(2x+11)-3x

We add all the numbers together, and all the variables

-3x+9x(2x+11)

We multiply parentheses

18x^2-3x+99x

We add all the numbers together, and all the variables

18x^2+96x

Back to the equation:

-(18x^2+96x)



We get rid of parentheses

18x^2-18x^2+18x-96x+39=0

We add all the numbers together, and all the variables

-78x+39=0

We move all terms containing x to the left, all other terms to the right

-78x=-39

x=-39/-78

x=1/2

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