(3x-2)+(x-13)+(x)=180

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Solution for (3x-2)+(x-13)+(x)=180 equation: 



(3x-2)+(x-13)+(x)=180

We move all terms to the left:

(3x-2)+(x-13)+(x)-(180)=0

We add all the numbers together, and all the variables

x+(3x-2)+(x-13)-180=0

We get rid of parentheses

x+3x+x-2-13-180=0

We add all the numbers together, and all the variables

5x-195=0

We move all terms containing x to the left, all other terms to the right

5x=195

x=195/5

x=39

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