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(3x-2)(x+7)=156
We move all terms to the left:
(3x-2)(x+7)-(156)=0
We multiply parentheses ..
(+3x^2+21x-2x-14)-156=0
We get rid of parentheses
3x^2+21x-2x-14-156=0
We add all the numbers together, and all the variables
3x^2+19x-170=0
a = 3; b = 19; c = -170;
Δ = b2-4ac
Δ = 192-4·3·(-170)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-49}{2*3}=\frac{-68}{6} =-11+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+49}{2*3}=\frac{30}{6} =5 $
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