(X+4)-(x+3)-x(x-2)=48

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Solution for (X+4)-(x+3)-x(x-2)=48 equation: 



(X+4)-(X+3)-X(X-2)=48

We move all terms to the left:

(X+4)-(X+3)-X(X-2)-(48)=0

We multiply parentheses

-X^2+(X+4)-(X+3)+2X-48=0

We get rid of parentheses

-X^2+X-X+2X+4-3-48=0

We add all the numbers together, and all the variables

-1X^2+2X-47=0

a = -1; b = 2; c = -47;
Δ = b2-4ac
Δ = 22-4·(-1)·(-47)
Δ = -184
Delta is less than zero, so there is no solution for the equation

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