(3x-2)(3x-5)=(3x-2)(3x-5)

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Solution for (3x-2)(3x-5)=(3x-2)(3x-5) equation: 



(3x-2)(3x-5)=(3x-2)(3x-5)

We move all terms to the left:

(3x-2)(3x-5)-((3x-2)(3x-5))=0

We multiply parentheses ..

(+9x^2-15x-6x+10)-((+9x^2-15x-6x+10))=0



We calculate terms in parentheses: -((+9x^2-15x-6x+10)), so:

(+9x^2-15x-6x+10)

We get rid of parentheses

9x^2-15x-6x+10

We add all the numbers together, and all the variables

9x^2-21x+10

Back to the equation:

-(9x^2-21x+10)



We get rid of parentheses

9x^2-9x^2-15x-6x+21x+10-10=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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