X2-6x-32=0

Solution for X2-6x-32=0 equation:

X2-6X-32=0

We add all the numbers together, and all the variables

X^2-6X-32=0

a = 1; b = -6; c = -32;
Δ = b2-4ac
Δ = -62-4·1·(-32)
Δ = 164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{164}=\sqrt{4*41}=\sqrt{4}*\sqrt{41}=2\sqrt{41}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{41}}{2*1}=\frac{6-2\sqrt{41}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{41}}{2*1}=\frac{6+2\sqrt{41}}{2}
$