(3x-2)(2x-1)=33

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Solution for (3x-2)(2x-1)=33 equation:



(3x-2)(2x-1)=33
We move all terms to the left:
(3x-2)(2x-1)-(33)=0
We multiply parentheses ..
(+6x^2-3x-4x+2)-33=0
We get rid of parentheses
6x^2-3x-4x+2-33=0
We add all the numbers together, and all the variables
6x^2-7x-31=0
a = 6; b = -7; c = -31;
Δ = b2-4ac
Δ = -72-4·6·(-31)
Δ = 793
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{793}}{2*6}=\frac{7-\sqrt{793}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{793}}{2*6}=\frac{7+\sqrt{793}}{12} $

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