(3x-18)+(6x+2)+(3x-4)=180

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Solution for (3x-18)+(6x+2)+(3x-4)=180 equation: 



(3x-18)+(6x+2)+(3x-4)=180

We move all terms to the left:

(3x-18)+(6x+2)+(3x-4)-(180)=0

We get rid of parentheses

3x+6x+3x-18+2-4-180=0

We add all the numbers together, and all the variables

12x-200=0

We move all terms containing x to the left, all other terms to the right

12x=200

x=200/12

x=16+2/3

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