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8-25=1/2(10x-2)+3x
We move all terms to the left:
8-25-(1/2(10x-2)+3x)=0
Domain of the equation: 2(10x-2)+3x)!=0We add all the numbers together, and all the variables
x∈R
-(1/2(10x-2)+3x)-17=0
We multiply all the terms by the denominator
-(1-17*2(10x-2)+3x)=0
We calculate terms in parentheses: -(1-17*2(10x-2)+3x), so:We add all the numbers together, and all the variables
1-17*2(10x-2)+3x
determiningTheFunctionDomain -17*2(10x-2)+3x+1
We add all the numbers together, and all the variables
3x-17*2(10x-2)+1
Wy multiply elements
3x-34x(1+1
Back to the equation:
-(3x-34x(1+1)
-(3x-34x2=0
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