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(3x-15)2x=180
We move all terms to the left:
(3x-15)2x-(180)=0
We multiply parentheses
6x^2-30x-180=0
a = 6; b = -30; c = -180;
Δ = b2-4ac
Δ = -302-4·6·(-180)
Δ = 5220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5220}=\sqrt{36*145}=\sqrt{36}*\sqrt{145}=6\sqrt{145}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-6\sqrt{145}}{2*6}=\frac{30-6\sqrt{145}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+6\sqrt{145}}{2*6}=\frac{30+6\sqrt{145}}{12} $
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