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5c-7=2(c+5)-5
We move all terms to the left:
5c-7-(2(c+5)-5)=0
We calculate terms in parentheses: -(2(c+5)-5), so:We get rid of parentheses
2(c+5)-5
We multiply parentheses
2c+10-5
We add all the numbers together, and all the variables
2c+5
Back to the equation:
-(2c+5)
5c-2c-5-7=0
We add all the numbers together, and all the variables
3c-12=0
We move all terms containing c to the left, all other terms to the right
3c=12
c=12/3
c=4
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