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(3x-14)(7x-6)=0
We multiply parentheses ..
(+21x^2-18x-98x+84)=0
We get rid of parentheses
21x^2-18x-98x+84=0
We add all the numbers together, and all the variables
21x^2-116x+84=0
a = 21; b = -116; c = +84;
Δ = b2-4ac
Δ = -1162-4·21·84
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-116)-80}{2*21}=\frac{36}{42} =6/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-116)+80}{2*21}=\frac{196}{42} =4+2/3 $
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