6-10c=9+2(3-7c)

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Solution for 6-10c=9+2(3-7c) equation: 



6-10c=9+2(3-7c)

We move all terms to the left:

6-10c-(9+2(3-7c))=0

We add all the numbers together, and all the variables

-10c-(9+2(-7c+3))+6=0



We calculate terms in parentheses: -(9+2(-7c+3)), so:

9+2(-7c+3)

determiningTheFunctionDomain
2(-7c+3)+9

We multiply parentheses

-14c+6+9

We add all the numbers together, and all the variables

-14c+15

Back to the equation:

-(-14c+15)



We get rid of parentheses

-10c+14c-15+6=0

We add all the numbers together, and all the variables

4c-9=0

We move all terms containing c to the left, all other terms to the right

4c=9

c=9/4

c=2+1/4

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