(3x-12)/(5)+(x/20)=(x/4)-2

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Solution for (3x-12)/(5)+(x/20)=(x/4)-2 equation: 


x in (-oo:+oo)

(3*x-12)/5+x/20 = x/4-2 // - x/4-2

(3*x-12)/5+x/20-(x/4)+2 = 0

(3*x-12)/5+x/20-x/4+2 = 0

(4*20*(3*x-12))/(4*5*20)+(4*5*x)/(4*5*20)+(5*20*(-x))/(4*5*20)+(2*4*5*20)/(4*5*20) = 0

4*20*(3*x-12)+4*5*x+5*20*(-x)+2*4*5*20 = 0

260*x-100*x-960+800 = 0

160*x-960+800 = 0

160*x-160 = 0

(160*x-160)/(4*5*20) = 0

(160*x-160)/(4*5*20) = 0 // * 4*5*20

160*x-160 = 0

160*x-160 = 0 // + 160

160*x = 160 // : 160

x = 160/160

x = 1

x = 1

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