7/(4x-3)=2/(x+5)

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Solution for 7/(4x-3)=2/(x+5) equation: 


D( x )

x+5 = 0

4*x-3 = 0

x+5 = 0

x+5 = 0

x+5 = 0 // - 5

x = -5

4*x-3 = 0

4*x-3 = 0

4*x-3 = 0 // + 3

4*x = 3 // : 4

x = 3/4

x in (-oo:-5) U (-5:3/4) U (3/4:+oo)

7/(4*x-3) = 2/(x+5) // - 2/(x+5)

7/(4*x-3)-(2/(x+5)) = 0

7/(4*x-3)-2*(x+5)^-1 = 0

7/(4*x-3)-2/(x+5) = 0

(7*(x+5))/((4*x-3)*(x+5))+(-2*(4*x-3))/((4*x-3)*(x+5)) = 0

7*(x+5)-2*(4*x-3) = 0

41-x = 0

(41-x)/((4*x-3)*(x+5)) = 0

(41-x)/((4*x-3)*(x+5)) = 0 // * (4*x-3)*(x+5)

41-x = 0

41-x = 0 // - 41

-x = -41 // * -1

x = 41

x = 41

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