(3x-12)+(2x+2)+(2x+8)=145

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Solution for (3x-12)+(2x+2)+(2x+8)=145 equation: 



(3x-12)+(2x+2)+(2x+8)=145

We move all terms to the left:

(3x-12)+(2x+2)+(2x+8)-(145)=0

We get rid of parentheses

3x+2x+2x-12+2+8-145=0

We add all the numbers together, and all the variables

7x-147=0

We move all terms containing x to the left, all other terms to the right

7x=147

x=147/7

x=21

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