(3x-10)=130-39x

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Solution for (3x-10)=130-39x equation: 



(3x-10)=130-39x

We move all terms to the left:

(3x-10)-(130-39x)=0

We add all the numbers together, and all the variables

(3x-10)-(-39x+130)=0

We get rid of parentheses

3x+39x-10-130=0

We add all the numbers together, and all the variables

42x-140=0

We move all terms containing x to the left, all other terms to the right

42x=140

x=140/42

x=3+1/3

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