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5k+9/5=3
We move all terms to the left:
5k+9/5-(3)=0
determiningTheFunctionDomain 5k-3+9/5=0
We multiply all the terms by the denominator
5k*5+9-3*5=0
We add all the numbers together, and all the variables
5k*5-6=0
Wy multiply elements
25k-6=0
We move all terms containing k to the left, all other terms to the right
25k=6
k=6/25
k=6/25
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